Well, it is pretty much the same.
Make a drawing. figure out, which value computes from which other value,
do the math and ... you have all that is needed.
I will not do it for you, since i strongly believe that every 8 year old
child can do that. It really is THAT simple as to add or subtract a few
numbers where all you need to do is figure out which numbers have to be
added or subtracted. If you can't do it in your mind, then make a
drawing. That drawing will tell you all that is needed.
If you have 2 relationships
1 | |
|
2 | |
|
3 | | |<------------- 5000 -------------->|
|
4 | | | |
|
5 | | |<------ 2300 ------>|<----- y ---->|
|
6 | |
|
7 | +-------------------------------------------->
|
and know those 2 numbers and want to know the value of y, then every 8
year old child is able to figure out, that y computes as 5000 - 2300.
Haveing some unknown value x in that system
1 | |
|
2 | |
|
3 | | |<------------- 5000 -------------->|
|
4 | | | |
|
5 | | |<---- 2300 + x ---->|<----- y ---->|
|
6 | |
|
7 | +-------------------------------------------->
|
does not change much in that calculation. Still y computes by subtracing
the thing left from it, which is 2300+x, from 5000. With a given and
known value for x, it is easy to do the math in order to come up with a
then computable value for y.
Und there really is not much more then that to solve your problem. Even
if your specific problem is a variation of that simple principle and
even if you need to figure out such relationships using a few easy steps
to come up with the numbers (or formulas) needed.
it really is not that hard, to figure out how to compute the value of z
in ...
1 | |
|
2 | |
|
3 | | |<------------- 5800 -------------------->|
|
4 | | | |
|
5 | | |<--- z --->|<- 80 ->|<---- 2300 + x ---->|
|
6 | |
|
7 | +-------------------------------------------------->
|
... even if the value for x may change, but is known.